I’m creating my target dictionary exactly as I have been creating my “source” dictionary how is it possible this is not working ? Python dictionaries leverage hash tables. TypeError: unhashable type: 'list' python dictionary . TypeError: unhashable type: 'list' usually means that you are trying to use a list as an hash argument. Quote:TypeError: unhashable type: 'list' and I have no idea what I'm doing wrong. TypeError: unhashable type: 'list' when using built-in set function , The Python TypeError: unhashable type: 'list' is raised when you try to assign a list as a key in a dictionary. Let us first understand what is hashable and unhasable. I had to comment the last part out because I managed to make it not work at all. TypeError: unhashable type: 'list' You can see that we got a TypeError: unhashable type: ‘list’. I'm creating my target dictionary exactly as I have been creating my "source" dictionary how is it possible this is not working? In simple terms, we term the items whose values cannot be changed as hashable and the objects whose values can be changed as unhashable. The unhashable object list can be stored in the dictionary after the list is converted to tuple. This is a list: If so, I'll show you the steps - how to investigate the errors and possible solution depending on the reason. I know I have errors all through the code. TypeError: unhashable type: 'list' Code : aTargetDictionary = {} for aKey in aSourceDictionary: TypeError: unhashable type: 'list' Code : python by Splendid Stag HK on Jul 13 2020 Donate . This was before the holidays. If we can't hash our key, we can't use it in our dictionary. TypeError: unhashable type: 'dict' The problem is that a list/dict can't be used as the key in a dict, since dict keys need to be immutable and unique. What you need is to get just the first item in list, written like so k = list[0].The same for v = list[j + 1:] which should just be v = list[2] for the third element of the list returned from the call to readline.split(" "). 0 Source: alysivji.github.io. The reason you’re getting the unhashable type: 'list' exception is because k = list[0:j] sets k to be a “slice” of the list, which is another, usually shorter, list. When we use a key that contains an unhashable type, i.e. On Career Karma, learn how to fix As you already know list is a mutable Python object. The tuple is a immutable object that can be stored in dictionary or set. You can add a list as a value in the dictionary. What you need is to get just the first item in list, written like so k = list[0]. Note that the restriction with keys in Python dictionary is only immutable data types can be used as keys, which means we cannot use a dictionary of list as a key. Let’s assume that the “source” dictionary has string as keys and has a list of custom objects per value. The reason you’re getting the unhashable type: 'list' exception is because k = list[0:j] sets k to be a “slice” of the list, which is logically another, often shorter, list. I get . a list, the underlying hash map cannot guarantee the key will map to the same bucket every single time. The tuple() function is used to convert the list … TypeError: unhashable type: 'list' or. I don't remember what I removed. Let's assume that the "source" dictionary has a string as keys and has a list of custom objects per value. But the same can be done very wisely with values in the dictionary. Use subscript to create a dictionary of lists. Therefore, … Till now, we have seen the ways to creating dictionary in multiple ways and different operations on the key and values in dictionary.Now, let’s see different ways of creating a dictionary of list. I get. 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